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How many kilocalories of heat would be needed to melt 0.32 kg of ice at 0°C and increase the temperature to 25°C? The specific heat of water is 1 cal/g.°C, specific heat of ice is 0.5 cal/g.°C, the latent heat of ice to water is 80 cal/g. Keep one digit after the decimal.

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To calculate the heat needed to melt the ice and raise the temperature, we need to break it down into two steps:

Step 1: Heat needed to melt the ice
The mass of ice is 0.32 kg, and the latent heat of ice to water is 80 cal/g. Therefore, the heat needed to melt the ice is:

0.32 kg x 80 cal/g = 25.6 kcal

Step 2: Heat needed to raise the temperature from 0°C to 25°C
The specific heat of water is 1 cal/g.°C, and the mass of water produced by melting the ice is also 0.32 kg. Therefore, the heat needed to raise the temperature from 0°C to 25°C is:

0.32 kg x 25°C x 1 cal/g.°C = 8 kcal

Total heat needed = Heat needed to melt the ice + Heat needed to raise the temperature
Total heat needed = 25.6 kcal + 8 kcal = 33.6 kcal

Therefore, 33.6 kilocalories of heat would be needed to melt 0.32 kg of ice at 0°C and increase the temperature to 25°C.
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