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The candies above are placed in a bag. They have hearts with each of the letters of the word Valentine in a bag. If you were to randomly reach your hand into the bag without seeing and grab a candy.


Q1: What is the probability as a fraction that the candy will not be a T.

Q2: What is the probability as a decimal that the candy will be purple

Q3: What is the probability as a percent that the candy will be an N or an E.

1 Answer

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Answer:

Q1. The probability as a fraction that the candy will not be a = 8/9

Q2. I need the colors of the candies and how many to answer this question. I will either edit this answer or provide the answer as a comment.

Q3. The probability as a percent that the candy will be an N or an E is 44.44%

Explanation:

The word VALENTINE has 9 letters in it but the letters N and E appear twice, all the other letters appear only once

Q1. The given event is that the candy selected will not be the letter T
This is the complement of the event that the chosen candy has the letter T


P(T) =(Number \: of \: candies \: with \: letter \: T)/(Total \; number \;of\;candies)}

= 1/9

T' is the complement of the event T and represents the event that the letter is not T

P(T') = 1 - P(T) = 1 - 1/9 = 8/9

This makes sense since there are 8 letters which are not T out of a total of n letters

Q2. Need color information for candies. How many candies of purple etc

Q3. P(letter N or letter E) = P(letter N) + P(letter E)
Since there are two candies with letter N P(N) = 2/9
Since there are two candies with letter E P(N) = 2/9

P(N or E) = 2/9 + 2/9 = 4/9

4/9 as a percentage = 4/9 x 100 = 44.44%

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