Question

Calculate the molality of a solution containing 26.489 g of ethanol (CH3CH2OH) and 395 g of water.Group of answer choices0.687 m1.46 × 10−3 m1.46 m227 m0.227 m

Answer 1

1.46 M

Step-by-step explanation:

M = mol ÷ Liters

26.489 / 46 = .576 mol of ethanol

density of water is 1g/ml, so the amount of liters of water (L) is 395 ÷ 1000 = .395 Liters

.576 ÷ .395 = 1.46 M