Final answer:
The probability that a randomly selected senior is either a varsity athlete or on the honor roll is 16/25, which can also be expressed as the decimal 0.64.
Step-by-step explanation:
The question you're asking relates to finding the probability that a randomly selected senior is either a varsity athlete or on the honor roll. This is a classic example of a probability question involving the union of two sets.
First, we need to consider the total number of students which is 200. There are 70 varsity athletes and 68 students on the honor roll. However, since 10 students are counted in both groups (varsity athletes and honor roll), we need to adjust our count so that we don't double-count these students when we combine the two groups. We use the formula:
Probability (A or B) = (Number of A) + (Number of B) - (Number of both A and B) / (Total number of students)
Using the figures from your question, we calculate the probability as follows:
Probability (Varsity Athlete or Honor Roll) = (70 varsity athletes + 68 honor roll students - 10 who are both) / 200 students = 128/200
The fraction 128/200 can be reduced to the simplest form by dividing both the numerator and the denominator by the greatest common divisor, which is 8. This simplifies the fraction to 16/25.
To convert it to a decimal, you divide 16 by 25, which is 0.64.
So, the probability that a randomly selected senior is either a varsity athlete or on the honor roll is 16/25 or 0.64.