Question

The bohr radius of the hydrogen atom is 0.0529 nm. that's the radius in the n=1 state. what is the radius of the hydrogen atom in the n=3 state.? 0.0529 nm 0.00588 nm 0.48 nm 0.16 nm

Answer 1

You want to find the radius of the hydrogen atom in the n=3 state, given that the Bohr radius of the hydrogen atom in the n=1 state is 0.0529 nm. To determine this, we will use the following formula:

radius = (n^2 * a0), where n is the principal quantum number (in this case, n=3), and a0 is the Bohr radius (0.0529 nm).

Step 1: Calculate the square of the principal quantum number:
n^2 = 3^2 = 9

Step 2: Multiply the result with the Bohr radius:
radius = (n^2 * a0) = (9 * 0.0529 nm) = 0.4761 nm

Therefore, the radius of the hydrogen atom in the n=3 state is approximately 0.48 nm.