Question

Write a balanced chemical equation for the reaction of aqueous potassium hydroxide with aqueous nickel (ii) chloride to form solid nickel (ii) hydroxide and aqueous potassium chloride.

Answer 1

The balanced chemical equation for the reaction of aqueous potassium hydroxide with aqueous nickel (II) chloride to form solid nickel (II) hydroxide and aqueous potassium chloride is 2KOH(aq) + NiCl2(aq) → Ni(OH)2(s) + 2KCl(aq).

Step-by-step explanation:

The balanced chemical equation for the reaction of aqueous potassium hydroxide (KOH) with aqueous nickel (II) chloride (NiCl2) to form solid nickel (II) hydroxide (Ni(OH)2) and aqueous potassium chloride (KCl) is:

2KOH(aq) + NiCl2(aq) → Ni(OH)2(s) + 2KCl(aq)

In this reaction, 2 moles of KOH react with 1 mole of NiCl2 to produce 1 mole of Ni(OH)2 and 2 moles of KCl. The equation is balanced as the number of atoms of each element is the same on both sides of the equation.

Answer 2

The balanced chemical equation for the reaction of aqueous potassium hydroxide with aqueous nickel (II) chloride to form solid nickel (II) hydroxide and aqueous potassium chloride is 2 KOH(aq) + NiCl2(aq) → Ni(OH)2(s) + 2 KCl(aq).

Step-by-step explanation:

The student is asking for a balanced chemical equation for the reaction between aqueous potassium hydroxide (KOH) and aqueous nickel (II) chloride (NiCl2) to form solid nickel (II) hydroxide (Ni(OH)2) and aqueous potassium chloride (KCl).

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on the reactants side as on the products side. The balanced chemical equation is:

2 KOH(aq) + NiCl2(aq) → Ni(OH)2(s) + 2 KCl(aq)

This reaction is an example of a double displacement reaction, where the anions and cations of two different molecules switch places, resulting in the formation of a new compound.