Question

A scientist uses a submarine to study ocean life.

She begins 83 feet below sea level.
• After descending for 5 seconds, she's 151 feet below sea level.
Find the rate of change in the submarine's elevation in feet per second. If
necessary, round your answer to the nearest tenth

Answer 1

The rate of change in the submarine's elevation is calculated by finding the difference in depth over the time taken. The submarine descends from 83 feet to 151 feet in 5 seconds, resulting in a rate of change of 13.6 feet per second after rounding to the nearest tenth.

Step-by-step explanation:

To find the rate of change in the submarine's elevation, we need to determine the difference in elevation and divide it by the time taken. The submarine starts at 83 feet below sea level and ends up at 151 feet below sea level after descending for 5 seconds.

First, we calculate the change in depth:

• Final depth = 151 feet
• Initial depth = 83 feet
• Change in depth = Final depth - Initial depth
• Change in depth = 151 feet - 83 feet
• Change in depth = 68 feet

Now, we find the rate of change over the 5-second period:

• Time = 5 seconds
• Rate of change = Change in depth / Time
• Rate of change = 68 feet / 5 seconds
• Rate of change = 13.6 feet per second

If necessary, rounding the answer to the nearest tenth gives us 13.6 feet per second as the rate at which the submarine's elevation changes.

Answer 2

The scientist descends from 83 feet below sea level to 151 feet below sea level, a change in depth of 151 - 83 = 68 feet. This change occurs over a time of 5 seconds.

The rate of change in depth, or the speed at which the submarine is descending, is given by the ratio of the change in depth to the time taken:

Rate of change in depth = (final depth - initial depth) / time taken

Rate of change in depth = (151 ft - 83 ft) / 5 s

Rate of change in depth = 13.6 ft/s (rounded to one decimal place)

Therefore, the rate of change in the submarine's elevation is 13.6 feet per second.