To solve this problem, we need to convert the initial velocity and final velocity from km/hr to m/s.
Initial velocity, u = 60 km/hr = 16.67 m/s (approx)
Final velocity, v = 120 km/hr = 33.33 m/s (approx)
Acceleration, a = 2 m/s²
We can use the following kinematic equation to find the distance traveled:
v² = u² + 2as
where s is the distance traveled.
Substituting the values, we get:
(33.33)² = (16.67)² + 2(2)s
Simplifying:
s = (33.33)² - (16.67)² / (2 x 2)
s = 416.67 m
Therefore, the distance traveled by the car is 416.67 m.
To find the time taken, we can use the following kinematic equation:
v = u + at
Substituting the values, we get:
33.33 = 16.67 + 2t
Simplifying:
t = (33.33 - 16.67) / 2
t = 8.33 s
Therefore, the time taken by the car to travel this distance is 8.33 seconds.