Question

A car travelling at 60km/hr undergoes uniform acceleration at a rate of 2m/s² until it's reach velocity of 120km/hr. Determine the distance traveled and time taken to make the distance

Answer 1

To solve this problem, we need to convert the initial velocity and final velocity from km/hr to m/s.

Initial velocity, u = 60 km/hr = 16.67 m/s (approx)

Final velocity, v = 120 km/hr = 33.33 m/s (approx)

Acceleration, a = 2 m/s²

We can use the following kinematic equation to find the distance traveled:

v² = u² + 2as

where s is the distance traveled.

Substituting the values, we get:

(33.33)² = (16.67)² + 2(2)s

Simplifying:

s = (33.33)² - (16.67)² / (2 x 2)

s = 416.67 m

Therefore, the distance traveled by the car is 416.67 m.

To find the time taken, we can use the following kinematic equation:

v = u + at

Substituting the values, we get:

33.33 = 16.67 + 2t

Simplifying:

t = (33.33 - 16.67) / 2

t = 8.33 s

Therefore, the time taken by the car to travel this distance is 8.33 seconds.