Question

A chemist mixes 66. g of water with 39. g of acetic acid and 5.1 g of butanoic acid. Calculate the percent by mass of each component of this solution. Round each of your answers to 2 significant digits. component mass percent water 0 % х Х 5 ? acetic acid % butanoic acid A chemist prepares a solution of zinc oxalate (ZC,0) by weighing out 1.79 kg of zinc oxalate into a 100 ml. volumetric flask and filling the Mask to the mark with water Calculate the concentration in g/dl of the chemist's inc oxidate solution. Round your answer to 3 significant digits.

Answer 1

Answer: the percent by mass of water, acetic acid, and butanoic acid in the solution are approximately 59.95%, 35.41%, and 4.63%, respectively.

Step-by-step explanation:

To calculate the percent by mass of each component in the solution, we first need to find the total mass of the solution:

Total mass = mass of water + mass of acetic acid + mass of butanoic acid

Total mass = 66 g + 39 g + 5.1 g

Total mass = 110.1 g

Now we can calculate the percent by mass of each component:

Percent by mass of water = (mass of water / total mass) x 100%

Percent by mass of water = (66 g / 110.1 g) x 100%

Percent by mass of water = 59.95% (rounded to 2 significant digits)

Percent by mass of acetic acid = (mass of acetic acid / total mass) x 100%

Percent by mass of acetic acid = (39 g / 110.1 g) x 100%

Percent by mass of acetic acid = 35.41% (rounded to 2 significant digits)

Percent by mass of butanoic acid = (mass of butanoic acid / total mass) x 100%

Percent by mass of butanoic acid = (5.1 g / 110.1 g) x 100%

Percent by mass of butanoic acid = 4.63% (rounded to 2 significant digits)

Therefore, the percent by mass of water, acetic acid, and butanoic acid in the solution are approximately 59.95%, 35.41%, and 4.63%, respectively.