Final answer:
The solubility of Cd₃(PO₄)₂ in water can be determined using the concept of solubility product constant (Ksp). We can calculate the concentrations of Cd²+ and PO₄³¯ ions in the saturated solution and solve for the molar solubility 'x' by using the Ksp expression. This will give us the solubility of Cd₃(PO₄)₂ in water.
Step-by-step explanation:
The solubility of Cd₃(PO₄)₂ in water can be determined using the concept of solubility product constant (Ksp). The Ksp of Cd₃(PO₄)₂ is given as 2.5 × 10⁻³³. In order to find the solubility, we need to calculate the concentrations of Cd²+ and PO₄³¯ ions in the saturated solution.
Using stoichiometry, we can determine that for every 1 mole of Cd₃(PO₄)₂ that dissolves, it produces 3 moles of Cd²+ and 2 moles of PO₄³¯ ions. Let's consider 'x' as the molar solubility of Cd₃(PO₄)₂, then the concentration of Cd²+ and PO₄³¯ ions will be 3x and 2x respectively.
Now, using the Ksp expression, Ksp = [Cd²+]³[PO₄³¯]², we can substitute the concentrations of Cd²+ and PO₄³¯ ions and solve for 'x'. Plugging in the given Ksp value of 2.5 × 10⁻³³, we can write the equation as:
2.5 × 10⁻³³ = (3x)³(2x)²
Solving this equation will give us the molar solubility 'x' of Cd₃(PO₄)₂ in water.