The half-reaction for the reduction of MnO4- to Mn2+ is:
MnO4-(aq) + 5 e- + 8 H+(aq) → Mn2+(aq) + 4 H2O(l)
In this reaction, MnO4- gains electrons and is reduced to Mn2+. Therefore, the reaction is a reduction.
The balanced equation shows that 5 electrons are needed for this reduction reaction.