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Write a rational equation that meets the given requirements:

- Horizontal Asymptote: y=0

- Exactly one Vertical Asymptote at x=-1

- Hole at: (1,2)

User Oggmonster
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Answer:

This function has a horizontal asymptote at y=0, a vertical asymptote at x=-1, and a hole at (1,2).

Explanation:

A rational equation with the given requirements can be written in the form:

f(x) = (x - 1) / [(x + 1)g(x)]

where g(x) is a factor in the denominator that ensures the vertical asymptote at x=-1.

To meet the condition that y=0 is a horizontal asymptote, we need to ensure that the degree of the denominator is greater than or equal to the degree of the numerator.

To create a hole at (1,2), we need to ensure that the factor (x-1) appears in both the numerator and the denominator, so that they cancel each other out at x=1.

One possible function that meets all of these requirements is:

f(x) = (x - 1) / [(x + 1)(x - 1)]

Simplifying this function, we get:

f(x) = 1 / (x + 1)

This function has a horizontal asymptote at y=0, a vertical asymptote at x=-1, and a hole at (1,2).

User YetAnotherSE
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