Question

Calculate the temp. (in kelvin) of a 1.50 mol of a sample of a gas 1.25 atm and a volume of 14 L

Answer 1

142.218

Step-by-step explanation:

The ideal gas law is PV=nRT

P= pressure in kpa

V= volume

n= number of moles

R= always equals 8.31

T= temperature in kelvins

P= (1.25)(101.3)= 126.625kPa

V= 14L

n= 1.50 mol

R= 8.31

T= ?

Multiply (126.625)(14) then divide that by (1.5)(8.31) to get your temperature in kelvins

Answer 2

To calculate the temperature in Kelvin of a 1.50 mol sample of a gas with a pressure of 1.25 atm and a volume of 14 L, we can use the ideal gas law equation PV = nRT. Rearranging the equation and plugging in the values, the temperature is approximately 12.83 K.

Step-by-step explanation:

To calculate the temperature in Kelvin, we can use the ideal gas law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin. Rearranging the equation, we have T = PV / (nR). Plugging in the values from the question, T = (1.25 atm) * (14 L) / (1.50 mol * 0.08206 L-atm/mol-K). After calculation, the temperature comes out to be approximately 12.83 K.