Question

A jet is flying in a direction n 70° e with a speed of 400 mi/h. find the north and east components of the velocity. (round your answer to two decimal places.)

north ____ mi/h
east _____ mi/h

Answer 1

To find the north and east components of the velocity of the jet flying at 70° east of north with a speed of 400 mi/h, we can use trigonometry. The north component of the velocity is approximately 366.60 mi/h, and the east component is approximately 157.98 mi/h.

Step-by-step explanation:

To find the north and east components of the velocity, we can use trigonometry. The velocity vector has a magnitude of 400 mi/h and is directed at an angle of 70° east of north. The north component of the velocity can be found using the sine function: sin(70°) = north component / 400. Rearranging the equation, we get: north component = 400 × sin(70°).

Using a calculator, we find that the north component is approximately 366.60 mi/h.

The east component can be found using the cosine function: cos(70°) = east component / 400. Rearranging the equation, we get: east component = 400 × cos(70°).

Using a calculator, we find that the east component is approximately 157.98 mi/h.

Answer 2

Answer: North 136.81 mph

East: 375.88 mph

Step-by-step explanation:

Hi there,

First you are going to want to set up a triangle based on the given information. You are giving a bearing for the degrees of the triangle, so the angle for the triangle you are going to solve will be 20 degrees.

You can use either Law of Sines or SOHCAHTOA to solve, but since you are setting up a right triangle I would use SOHCAHTOA. You are trying to find the vertical and horizontal components so start with sine to find the y-value. It should look like:

sin(20)=(opposite side of the given angle/400)

It will be travelling North at 136.81 mph

Similarly, we now need to find the horizontal component. Start by using cosine. It should look like

cos(20)=(side adjacent to the given angle/400)

It should be traveling East at 375.88 mph

Hope this helps.