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The density of helium is 0.164 kg·m-3• what is this density in lb·ft-3? 1 m = 3.28 ft

User Jeena Rita
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Final answer:

To convert the density of helium from kg/m³ to lb/ft³, multiply the given density by the conversion factor from kilograms to pounds, and then divide by the conversion factor for cubic meters to cubic feet, resulting in a density of approximately 0.01024 lb/ft³.

Step-by-step explanation:

The question involves converting the density of helium from kilograms per cubic meter (kg/m³) to pounds per cubic foot (lb/ft³). The student provided the density of helium as 0.164 kg/m³ and the conversion for meters to feet as 1 m = 3.28 ft. Additionally, the conversion factor from kilograms to pounds is 1 kg = 2.20462 pounds.

To convert the density from kg/m³ to lb/ft³, we can use the following steps:

  1. Convert the mass from kilograms to pounds.
  2. Convert the volume from cubic meters to cubic feet by raising the linear conversion factor (meters to feet) to the power of three, since we're dealing with cubic units.

Step 1: Convert the density from kg/m³ to lb/m³ by multiplying 0.164 kg by the conversion factor:

0.164 kg/m³ * 2.20462 lb/kg = 0.3616 lb/m³

Step 2: Convert from m³ to ft³:

Since (1 m) ³ = (3.28 ft) ³, then we have:

1 m³ = 3.28³ ft³ = 35.3147 ft³

Now, divide the density in lb/m³ by the cubic conversion factor:

0.3616 lb/m³ / 35.3147 ft³/m³ = 0.01024 lb/ft³

Therefore, the density of helium is approximately 0.01024 lb/ft³.

User Dave Winer
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