Question

The admission fee at the fair is $1.50 for children and $4 for adults. On a certain day, 2200 people enter the fair and $5050 is collected. How many children, c, and how many adults, a, attended?

Which system of equations can be used to solve the problem?
Responses



c + a = 2200

1.50c + 4a = 5050
, , c + a = 2200, , 1.50 c + 4 a = 5050,



c + a = 2200

1.50c + a = 5050
, , c + a = 2200, , 1.50 c + a = 5050,



c + 4a = 2200

1.50c + a = 5050

Answer 1

c+a=2,200

1.50c+4c=5,050

Explanation:

We know that on one day, 2,200 people entered the fair.

So, using the variables, c/a, we know that c+a=2,200

This gives us our first equation in this system of equations.

We are also given that a total of $5,050 was made. $1.50 is a children ticket/admission fee and $4 per adult.

So:

1.50c+4c=5,050

Thus our system of equations looks like:

c+a=2,200

1.50c+4c=5,050

Hope this helps! :)