Answer:
3.
Chromium Nitrate: Cr(NO3)3
Iron II Sulfate: FeSO4
2Cr(NO3)3 (aq) + 3FeSO4 (aq) --> 3Fe(NO3)2 (aq) + Cr2(SO4)3 (s)
Net ionic form: 2Cr 3+ (aq) + 3SO4 1- (aq) --> Cr2(SO4)3 (s)
4.
This problem is interesting because it utilizes bronsted lowry acids and bases. The first thing to note is both HCl and NaOH will dissociate in water prior to the reaction.
HCl + H2O --> Cl 1- + H3O 1+
NaOH + H2O --> Na 1+ + OH 1-
When you have a reaction between a strong acid (HCl) and a strong base (NaOH), the net ionic equation that it follows will be:
H3O 1+ (aq) + OH 1- (aq) --> 2H2O (l).