Answer:
1) 1256.02 kJ
2)76.20 lb
3)2336.30 lb
Step-by-step explanation:
The kinetic energy of a 4,934 pound pickup truck going 55 mph is:
First, we need to convert the mass of the truck from pounds to kilograms:
4,934 lb = 2,236.17 kg
The kinetic energy is given by the formula: KE = 0.5 * m * v^2
where m is the mass of the object and v is the velocity.
Plugging in the values, we get:
KE = 0.5 * 2,236.17 kg * (55 mph)^2 = 1,256,024.47 J
Converting to kJ, we get:
KE = 1,256,024.47 J / 1000 = 1256.02 kJ
A 4,992 lb car has a rolling resistance coefficient of 0.015. How much force, in lb, will it take to push this car at 30 mph?
The force required to overcome rolling resistance is given by the formula:
F = Crr * W
where Crr is the rolling resistance coefficient and W is the weight of the car.
First, we need to convert the weight of the car from pounds to Newtons:
4,992 lb = 22,612.88 N
Plugging in the values, we get:
F = 0.015 * 22,612.88 N = 339.19 N
Converting to pounds, we get:
F = 339.19 N / 4.45 = 76.20 lb
The 2022 Hummer EV comes with a 212 kWh battery. How much will this battery weigh in lbs?
We cannot directly convert from kilowatt-hours to pounds, as they are two different units. However, we can use the energy density of the battery to estimate its weight.
Assuming an energy density of 200 Wh/kg for the battery, we can calculate the mass of the battery as:
212 kWh * 1000 Wh/kWh / 200 Wh/kg = 1060 kg
Converting to pounds, we get:
1060 kg * 2.205 lb/kg = 2336.30 lb