Question

7 X 12 x= [?] Round to the nearest tenth.​

Answer 1

`\begin{array}{llll} \textit{using the pythagorean theorem} \\\\ c^2=a^2+o^2\implies c=√(a^2 + o^2) \end{array} \qquad \begin{cases} c=\stackrel{hypotenuse}{x}\\ a=\stackrel{adjacent}{12}\\ o=\stackrel{opposite}{7} \end{cases} \\\\\\ x=√( 12^2 + 7^2)\implies x=√( 144 + 49 ) \implies x=√( 193 )\implies x\approx 13.9`