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Find the equation for the line containing the points (-4,-2) and (-3,5)

Find the equation for the line containing the points (-4,-2) and (-3,5)-example-1
User SynackSA
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1 Answer

12 votes
12 votes

Answer:

Explanation:

Given the points

(4, 2)

(3, 5)

We know that the slope-intercept form of the line equation is

where m is the slope and b is the y-intercept

substituting m=-3 and the point (4, 2) to get the y-intercept i.e. b

2=(-3)4 + b

2 = -12 + b

b = 2+12

b = 14

Now, substituting b=14 and m=-3 in the slope-intercept form to determine the equation of a line in the slope-intercept.

y=(-3)x+(14)

y=-3x+14

Thus, the equation of the line containing (4,2) and (3,5) in the slope-intercept form will be:

y=-3x+14

User Howaryoo
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