To determine the photon energy of the orange light emitted by a source containing krypton-86 atoms, we can use the equation:
E = hc/λ
where E is the energy of a photon, h is Planck's constant (6.626 x 10^-34 joule seconds),
c is the speed of light (299,792,458 meters per second),
and λ is the wavelength of the light in meters.
The wavelength of the orange light emitted by a source containing krypton-86 atoms is given as 1,650,763.73 wavelengths per meter. Therefore, we can calculate the wavelength of this light as:
λ = 1/1,650,763.73 meters per wavelength
λ = 6.052 x 10^-7 meters
Now, we can use this wavelength value in the above equation to calculate the energy of a single photon of this light:
E = hc/λ
E = (6.626 x 10^-34 joule seconds) x (299,792,458 meters per second) / (6.052 x 10^-7 meters)
E = 3.126 x 10^-19 joules per photon
Therefore, the photon energy of the orange light emitted by a source containing krypton-86 atoms is 3.126 x 10^-19 joules per photon.