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the meter was once defined as 1 650 763.73 wavelengths of the orange light emitted by a source containing krypton-86 atoms. what is the photon energy of that light?

User Dvdchr
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To determine the photon energy of the orange light emitted by a source containing krypton-86 atoms, we can use the equation:

E = hc/λ

where E is the energy of a photon, h is Planck's constant (6.626 x 10^-34 joule seconds),

c is the speed of light (299,792,458 meters per second),

and λ is the wavelength of the light in meters.

The wavelength of the orange light emitted by a source containing krypton-86 atoms is given as 1,650,763.73 wavelengths per meter. Therefore, we can calculate the wavelength of this light as:

λ = 1/1,650,763.73 meters per wavelength

λ = 6.052 x 10^-7 meters

Now, we can use this wavelength value in the above equation to calculate the energy of a single photon of this light:

E = hc/λ

E = (6.626 x 10^-34 joule seconds) x (299,792,458 meters per second) / (6.052 x 10^-7 meters)

E = 3.126 x 10^-19 joules per photon

Therefore, the photon energy of the orange light emitted by a source containing krypton-86 atoms is 3.126 x 10^-19 joules per photon.

User Soydachi
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