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The heat of vaporization for ethanol is 0.826 kJ/g . Calculate the heat energy in joules required to boil 75.25 g of ethanol.
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The heat of vaporization for ethanol is 0.826 kJ/g

. Calculate the heat energy in joules required to boil 75.25 g
of ethanol.

User Relisora
by
8.7k points

2 Answers

4 votes
Y’all hella smart because y’all nerds
User FuzzyTree
by
9.4k points
0 votes

Answer:

87469.73J

Step-by-step explanation:

72.25g/0.826kJ/g=87.4697337kJ

User Samba
by
8.3k points
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