Question

Given that log2 = x and log3 = y, express log60 in terms of x and y

Answer 1

We can use logarithmic identities to express log60 in terms of x and y:

log60 = log(2^2 * 3 * 5)
= log(2^2) + log(3) + log(5)
= 2log2 + log3 + log5 (since log5 is not given)

Now we substitute x for log2 and y for log3:

log60 = 2x + y + log5

So the expression for log60 in terms of x and y is 2x + y + log5.