Answer:
CH3CH(OH)CN
Step-by-step explanation:
This product is also known as acrylamide or prop-2-enamide. The reaction is a type of nucleophilic addition, in which the CN^- ion acts as a nucleophile and attacks the carbonyl carbon of CH3CH=O, forming a tetrahedral intermediate. Then, a proton transfer occurs, resulting in the formation of CH3CH(OH)CN and a water molecule. The mechanism of the reaction can be shown as follows: