Question

Please help with this question

Answer 1

Step-by-step explanation: Here if we put
`x=0` then we will get initial temperature. That is
`T_0=70+20=90`.

The temperature will cools down
`70(0.8)^(10)+20=27.52(approx)`.

So the final temperature after 10 minutes will be :
`90-27.52=62.48(approx)`.

Final Answer: The temperature is 62.48 degree Celsius.