Question

Determine the equation of the circle with (0,-6) containing the point (-√28,-3)

Answer 1

Explanation:

I assume ( 0, -6) is the center

so you have

(x- 0)^2 + ( y - - 6)^2 = r^2

r is the radius and is the distance from the center to the point given

use distance formula to find r

d^2 = ( 0- - sqrt(28))^2 + ( -6 - -3)^2

d^2 = 28 + 9

d = sqrt (37) <======radius

then your equation becomes

x^2 + ( y+6)^2 = 37