166k views
4 votes
Need the answer to this using SOH-CAH-TOA

Need the answer to this using SOH-CAH-TOA-example-1
User Collierre
by
8.1k points

1 Answer

1 vote

Answer:


x \approx 16.26\°

Explanation:

We can solve for angle x in this right triangle using the trigonometric ratio sine.


\sin(\theta) = \frac{\text{opposite}}{\text{hypotenuse}} ... This is the SOH part of SOH-CAH-TOA

↓ plugging in the given values


\sin(x) = (7)/(25)

↓ taking the inverse sine of both sides


\sin^(-1)(\sin(x)) = \sin^(-1)\left((7)/(25)\right)

↓ canceling ...
\sin^(-1)(\sin(\theta)) = \theta


x = \sin^(-1)\left((7)/(25)\right)

↓ plugging into a calculator


\boxed{x \approx 16.26\°}

User Lek
by
8.0k points

Related questions

1 answer
4 votes
188k views
asked Feb 15, 2024 206k views
DuuEyn asked Feb 15, 2024
by DuuEyn
8.0k points
1 answer
5 votes
206k views
1 answer
5 votes
118k views