Question

Your car will start at rest and accelerate at a rate of 7.33 m/s/s until it reaches a top speed of 37.30 m/s. Predict the time required to reach top speed and distance the car will travel after a total of 20 seconds of motion have passed.

Answer 1

Step-by-step explanation:

we know the velocity of an object is:

v=u+a×t

and distance traveled by an object is:

s=u×t+1/2×a×t²

where v⇒finial velocity of the object.

u⇒initial velocity of the object.

a⇒acceleration of the body.

s⇒distance covered by the body.

t⇒time taken by the body.

According to the question,

u=0 [since the body starts moving from rest]

v=37.30 m/s

a=7.33 m/s²

Part -1

v=u+a×t

⇒37.30=0+7.33×t

⇒37.30/7.33=t

∴t=5.08sec

∴The time required to reach the top speed is 5.08 seconds.

Part-2

t=20 seconds

s=u×t+1/2×a×t²

⇒s=o×t+1/2×7.33×20²

∴s=1466 m.

∴The distance the car will travel after 20 seconds of motion has passed is 1466m.