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4 votes
What is:

tan B=
cos B=
cos A=
sin B=
tan A=
sin A=
of this triangle

What is: tan B= cos B= cos A= sin B= tan A= sin A= of this triangle-example-1
What is: tan B= cos B= cos A= sin B= tan A= sin A= of this triangle-example-1
What is: tan B= cos B= cos A= sin B= tan A= sin A= of this triangle-example-2
User Jpcgandre
by
7.8k points

1 Answer

3 votes

Answer :

In the first figure,

△BCA

a = Perpendicular

b = base

c = hypotenuse

In the second figure,

△ABC

a = base

b = perpendicular

c = base

tan B = Perpendicular/Base = b/a

cos B = Base/Hypotenuse = a/c

cos A = Base/Hypotenuse = a/c

sin B = Perpendicular/Hypotenuse = b/c

tan A = Perpendicular/Base = a/b

sin A = Perpendicular/Hypotenuse = a/c

What is: tan B= cos B= cos A= sin B= tan A= sin A= of this triangle-example-1
What is: tan B= cos B= cos A= sin B= tan A= sin A= of this triangle-example-2
User Zeeshan Ahmad II
by
8.9k points

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