Question

Write the equation of the line that has slope 3 and passes through the point
(-2,5).

Answer 1

Answer: y = 3x + 11

Explanation:
y = kx+m is the equation of a line. The coefficient of x is the slope i.e 3. So we know that a part of the equation is y = 3x + m.

How to find M?
Well, we already have a point on the equation. Meaning we already have an x and a y. -2 = x and 5 = y.

The equation then becomes 5 = (3 x -2) + m.

Solve for m and the answer will be m = 11.

Now we have both m and K meaning that the whole equation is solved and it’s y = 3x + 11

Answer 2

from
y=mx +c
where m is the slope, c is a constant, and x and y are variables,
we know the slope is 3 so m=3
rewriting it
y=3x +c
to find c we substitute values x=-2 and y=3 into the equation y=3x +c
so
3= 3(-2) + c
c=9
thus, y=3x+ 9