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Triangle BCD is shown, with side lengths in centimeters (cm). Line segment EF is parallel to line segment BD.

4 cm
B
3 cm
E
C
12 cm
What is the length, in centimeters, of line segment CD?
FL
5 cm
D

User AMG
by
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1 Answer

1 vote

Answer:

Explanation:

Since line segment EF is parallel to line segment BD, we can use the property that corresponding angles are congruent to set up the following proportion:

EF/BD = FL/BC

Substituting the given values:

EF/4 = 5/12

Cross-multiplying:

EF = 4 x 5/12 = 5/3 cm

We can use the fact that triangles BCD and EFD are similar (having two congruent angles) to set up another proportion:

CD/EF = BC/BD

Substituting the given values:

CD/(5/3) = 12/BD

Solving for CD:

CD = (5/3) x 12/BD = 20/BD cm

We can use the Pythagorean theorem to find the length of BD:

BD^2 = BC^2 + CD^2

Substituting the given values:

BD^2 = 3^2 + 12^2 = 153

Taking the square root of both sides:

BD = sqrt(153) = 3sqrt(17) cm

Substituting this value into the expression for CD:

CD = 20/BD = 20/(3sqrt(17)) = (20/3)sqrt(17) cm

Therefore, the length of line segment CD is (20/3)sqrt(17) cm.

User FXbeckers
by
8.6k points