Question

In circle m r=5 in and m

Answer 1

GiveN:-

• r = 5
• angle AMB = 80°

To FinD:-

• Area of Sector = ??

SolutioN:-

➢ Calculating Area of Sector :-

`\sf \longrightarrow \: Area \: of \: Sector \: = ( \theta \: )/(360 \degree \: ) * \pi \: {r}^(2) \\`

`\sf \longrightarrow \: Area \: of \: Sector \: = ( 80 \: )/(360 \degree \: ) * (22)/(7) *\: {5}^(2) \\`

`\sf \longrightarrow \: Area \: of \: Sector \: = ( 8 \: )/(36 \degree \: ) * (22)/(7) * \: 5 * 5 \\`

`\sf \longrightarrow \: Area \: of \: Sector \: = ( 8 \: )/(36 \degree \: ) * (22)/(7) *\: 25 \\`

`\sf \longrightarrow \: Area \: of \: Sector \: = ( 4 \: )/(18 \degree \: ) * (22)/(7) * \: 25 \\`

`\sf \longrightarrow \: Area \: of \: Sector \: = ( 2\: )/(9 \degree \: ) * (22)/(7) \: * 25 \\`

`\sf \longrightarrow \: Area \: of \: Sector \: = ( 2 * 22 * 25\: )/(9 * 7 \: ) \\`

`\sf \longrightarrow \: Area \: of \: Sector \: = ( 44 * 25\: )/(9 * 7 \: ) \\`

`\sf \longrightarrow \: Area \: of \: Sector \: = ( 1100\: )/(63 \: ) \\`

`\sf \longrightarrow \: Area \: of \: Sector \: = 17.5 \: \: {m}^(2) \\`

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Option D :- 17.5 m²