In circle m r=5 in and m

Question

asked Nov 7, 2024 133k views

1 Answer

Rmalchow · Answer 1 · 2024-11-12T02:52:34+0000

Answer:

➢ Calculating Area of Sector :-

$\sf \longrightarrow \: Area \: of \: Sector \: = ( \theta \: )/(360 \degree \: ) * \pi \: {r}^(2) \\$

$\sf \longrightarrow \: Area \: of \: Sector \: = ( 80 \: )/(360 \degree \: ) * (22)/(7) *\: {5}^(2) \\$

$\sf \longrightarrow \: Area \: of \: Sector \: = ( 8 \: )/(36 \degree \: ) * (22)/(7) * \: 5 * 5 \\$

$\sf \longrightarrow \: Area \: of \: Sector \: = ( 8 \: )/(36 \degree \: ) * (22)/(7) *\: 25 \\$

$\sf \longrightarrow \: Area \: of \: Sector \: = ( 4 \: )/(18 \degree \: ) * (22)/(7) * \: 25 \\$

$\sf \longrightarrow \: Area \: of \: Sector \: = ( 2\: )/(9 \degree \: ) * (22)/(7) \: * 25 \\$

$\sf \longrightarrow \: Area \: of \: Sector \: = ( 2 * 22 * 25\: )/(9 * 7 \: ) \\$

$\sf \longrightarrow \: Area \: of \: Sector \: = ( 44 * 25\: )/(9 * 7 \: ) \\$

$\sf \longrightarrow \: Area \: of \: Sector \: = ( 1100\: )/(63 \: ) \\$

$\sf \longrightarrow \: Area \: of \: Sector \: = 17.5 \: \: {m}^(2) \\$

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Option D :- 17.5 m²