Answer: CH₃CH₂OH
Explanation: The intermolecular forces of hydrogen bonding, dipole-dipole interactions, and London dispersion have a significant role in influencing solubility in CH₃CH₂OH.
Both ionic compounds, NaCl and KCl, dissolve in water through ion-dipole interactions. These compounds have large lattice energies, which implies it takes a lot of energy to dissolve them in CH₃COOH and break the ionic bonds.
(c) The polar molecule NH3 is capable of forming a hydrogen bond with CH₃CH₂OH. Therefore, it is anticipated that NH3 will be more soluble in CH₃CH₂OH than NaCl or KCl.
(d) The polar compound CH₃COOH is capable of forming a hydrogen bond with CH₃CH₂OH.
Therefore, NaCl is predicted to be the least soluble in CH₃CH₂OH based solely on intermolecular forces.