Answer:

Explanation:
General slope-intercept form of a straight line is
y = mx + b
where m = slope, b = y-intercept
The diagonals of a rhombus bisect each other at 90°
The equation of diagonal AC can be found as follows
Slope of AC =

Therefore the diagonal AC has the equation
y = -2x + b
where b is the y intercept
We can find b by plugging in (-2, 4) into the above equation:
4 = -2(-2) + b
4 = b + b
b = 0
So the equation of the diagonal is y = -2x
This passes through the origin (0,0)
Since A and C are equidistant from the origin, the origin is the midpoint of the diagonal AC
Since the other diagonal BD has to bisect this diagonal at 90°, it too has to pass through the midpoint (0, 0)
The slope of a line perpendicular to y = mx + b is -1/m
Therefore the slope of the perpendicular line to y = -2x is - (1/-2) = 1/2 and the y-intercept is 0 since it passes through the origin
Therefore the equation of diagonal BD is
