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What is the range of the function f(x) = 3x + 2 over the interval -3 < x < 5?

1 Answer

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Answer:

-7 < f(x) < 17

Explanation:

f(x) = 3x + 2

The given domain is -3 < x < 5

If x = -3, f(x) = f(-3) = 3(-3) + 2 = -9 + 2 = -7

If x = 5, f(x) = f(5) = 3(5) + 2 = 15 + 2 = 17

The range of f(x) is the set of permissible values for f(x) for the given domain -3 < x < 5

Therefore range of f(x): -7 < f(x) < 17

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