Final answer:
The mass of solute (Sodium Phosphate) in a 500 mL solution of 0.200 M concentration is calculated to be 16.394 grams.
Step-by-step explanation:
To find the mass of solute in a 500 mL solution of 0.200 M Sodium Phosphate, we need to follow these steps:
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- First, convert the volume from milliliters to liters because molarity (M) is defined in terms of liters of solution. So, 500 mL is converted to 0.500 L.
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- Next, calculate the number of moles of the solute using the molarity formula which is Molarity (M) = moles of solute / liters of solution. For a 0.200 M solution, this will be 0.200 moles/L × 0.500 L = 0.100 moles.
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- Then, find the molar mass of Sodium Phosphate (Na3PO4). The molar mass is the sum of the masses of all the atoms in the molecular formula. The approximate atomic masses are Na (sodium) = 23 g/mol, P (phosphorus) = 31 g/mol, and O (oxygen) = 16 g/mol. Thus, Na3PO4 has a molar mass of (3×23) + 31 + (4×16) = 163.94 g/mol.
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- Finally, calculate the mass of Sodium Phosphate by multiplying the moles by its molar mass. The mass of solute = moles × molar mass = 0.100 moles × 163.94 g/mol = 16.394 grams.
Therefore, the mass of Sodium Phosphate in a 500 mL solution of 0.200 M concentration is 16.394 grams.