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A number cube is rolled. Event A is rolling an odd number, and event B is rolling a factor of 12. What is P(AU B)?

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Answer: 1

Step-by-step explanation:

A = set of odd numbers = {1,3,5}

B = set of factors of 12 = {1,2,3,4,6}

A U B = union of set A and set B

A U B = {1,3,5} union {1,2,3,4,6}

A U B = {1,3,5, 1,2,3,4,6}

A U B = {1,2,3,4,5,6}

The set union operation combines two sets into one bigger set. Duplicates are tossed out.

There are 6 elements in the set A U B = {1,2,3,4,5,6} out of 6 faces of the number cube.

Therefore, the probability event A U B happens is 6/6 = 1 = 100%; i.e. it is guaranteed to happen. Each face of the number cube is either odd, a factor of 12, or both.

Side notes:

  • A U B can be read out as "event A or event B"; so P(A U B) is "the probability event A happens or B happens or both".
  • A intersect B = {1,3} = values that are in both set A and set B at the same time. These are both odd and a factor of 12.
User Tomasz Szulc
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