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Shawna can paint a fence in 6 hours. Kevin can paint the same fence in 5 hours. How long will it take them working together? Which of the following equations could be used to solve this problem? ​

Shawna can paint a fence in 6 hours. Kevin can paint the same fence in 5 hours. How-example-1
User Dierre
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8.1k points

2 Answers

4 votes

Answer:

Explanation:

Shawna can paint a fence in 6 hours. Kevin can paint the same fence in 5 hours. How-example-1
User Rorie
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8.9k points
2 votes

Answer:

Second Option

\left((1)/(6) \right)\cdot t + \left((1)/(5) \right)\cdot t = 1

Explanation:

Shawna can paint the fence in 6 hours. So her rate of work is 1/6 of the fence in one hour

Kevin can paint the same fence in 5 hours so his rate of work is 1/5

Working together their combined rate
= 1/6 + 1/5

Let the time taken for both of them working together to paint the entire fence be t hours

In t hours
amount of work done by each = rate x time
For Shawna:

(1)/(6) \cdot t

For Kevin:

(1)/(5) \cdot t

The total work done must add up to the whole fence which can be represented as 1

Therefore the equation for computing the time taken for both of them to work together is given by


(1)/(6) \cdot t + (1)/(5) \cdot t = 1

This is the second option


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As an aside
While you have not been asked to solve the problem, we can still do it as an exercise:

(1)/(6) \cdot t + (1)/(5) \cdot t = 1\\\\\rightarrow \left((1)/(6) + (1)/(5) \right) \cdot t = 1\\\\\rightarrow (11)/(30) \cdot t = 1\\\\t = (30)/(11) = 2 (8)/(11) \;hours

User Suren Baskaran
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8.1k points