Question

dry oxygen gas is collected over water vapor at 0°C, and a partial pressure of the oxygen gas was found to have a pressure of 741mmHg what was the atmosphere pressure when the gas was collected

Answer 1

To find the atmospheric pressure, we need to add the pressure of the water vapor to the partial pressure of the oxygen gas.

At 0°C, the vapor pressure of water is 4.58 mmHg.

So, the total pressure of the gas mixture is:

P_total = P_oxygen + P_water vapor

P_total = 741 mmHg + 4.58 mmHg

P_total = 745.58 mmHg

Therefore, the atmospheric pressure when the gas was collected was 745.58 mmHg.