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what is the pressure in atmosphere exerted by 2.2 moles of gas with a temperature of 45 C and a volume of 7.5 L

User Tjt
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Assuming the gas behaves ideally, we can use the ideal gas law:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin by adding 273.15:

T = 45°C + 273.15 = 318.15 K

Next, we can plug in the values we have and solve for pressure:

P = nRT/V

P = (2.2 mol)(0.08206 L·atm/mol·K)(318.15 K)/(7.5 L)

P ≈ 16.4 atm

Therefore, the pressure exerted by 2.2 moles of gas with a temperature of 45°C and a volume of 7.5 L is approximately 16.4 atm.

User Jason Peacock
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