167k views
3 votes
The platform has a tension rating of 2000N. The platform itself is 4 meters long and has a mass of 200 kg. The rope on the left side is attached directly to the left edge, while on the right side it is 1 meter inside the edge. If a 70 kg person stands on the far right edge, will the platform be safe?

User Banny
by
8.3k points

1 Answer

4 votes

Answer:

Since the total tension on the ropes (4630.5 N) is greater than the maximum tension that the platform can withstand (2000 N), the platform is not safe. Therefore, the person should not stand on the far right edge of the platform.

Step-by-step explanation:

To determine whether the platform is safe, we need to calculate the tension on the ropes and compare it to the maximum tension that the platform can withstand (2000N).

First, let's calculate the weight of the platform:

Weight of the platform = mass x gravity

Weight of the platform = 200 kg x 9.8 m/s^2

Weight of the platform = 1960 N

Next, let's calculate the weight of the person standing on the platform:

Weight of the person = mass x gravity

Weight of the person = 70 kg x 9.8 m/s^2

Weight of the person = 686 N

The total weight on the platform is:

Total weight = weight of platform + weight of person

Total weight = 1960 N + 686 N

Total weight = 2646 N

Now, let's calculate the tension on the ropes. Since the rope on the left side is attached directly to the left edge, it will bear the entire weight of the platform and the person. The rope on the right side will bear a portion of the weight, equal to the distance of the person from the edge divided by the length of the platform:

Tension on left rope = Total weight = 2646 N

Tension on right rope = (Distance from person to right edge / Length of platform) x Total weight

Tension on right rope = (3 m / 4 m) x 2646 N

Tension on right rope = 1984.5 N

The total tension on the ropes is:

Total tension = Tension on left rope + Tension on right rope

Total tension = 2646 N + 1984.5 N

Total tension = 4630.5 N

User Wonce
by
8.1k points