Answer:
(a) First, we need to find f(9+h) and f(9):
f(9+h) = (9+h)^2 + 3 = 81 + 18h + h^2 + 3 = h^2 + 18h + 84
f(9) = 9^2 + 3 = 84
Now, we can substitute these values into the difference quotient and simplify:
(f(9+h) - f(9))/h = ((h^2 + 18h + 84) - 84)/h = (h^2 + 18h)/h = h + 18
(b) Using the limit definition of the derivative:
f′(9) = lim(h→0) (f(9+h) - f(9))/h = lim(h→0) (h + 18) = 18
(c) The equation of the tangent line to the curve at the point (9,f(9)) is given by:
y - f(9) = f′(9)(x - 9)
Substituting f(9) and f′(9) into this equation, we get:
y - 84 = 18(x - 9)
y = 18x - 54 + 84
y = 18x + 30