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The width of a rectangle is 1 units less than the length. The area of the rectangle is 56
square units. What is the length, in units, of the rectangle?
Quadratic Word Problems
Apr 30, 11:47:01 PM
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Answer:

Let's assume that the length of the rectangle is "x" units.

According to the problem, the width of the rectangle is 1 unit less than the length. Therefore, the width can be represented as (x-1) units.

We know that the area of a rectangle is equal to its length multiplied by its width. So, the area of this rectangle is given as 56 square units.

Using the formula for the area of a rectangle, we can write:

Length x Width = Area

x(x-1) = 56

Expanding the left side of the equation, we get:

x^2 - x = 56

Rearranging the terms, we get a quadratic equation:

x^2 - x - 56 = 0

Now we can solve for x by factoring the quadratic equation:

(x-8)(x+7) = 0

This gives us two possible values for x: x=8 and x=-7.

Since length cannot be negative, we reject x=-7 and conclude that the length of the rectangle is 8 units.

Therefore, the length of the rectangle is 8 units and the width is (8-1) = 7 units.

Explanation:

User Burak SARICA
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