Question

4. A silver bar with a mass of 300 grams is heated from 30 °C to 55 °C, How much heat does the silver bar absorb in joules? In kilojoules? The specific heat of silver is 0.235 j/g. C.​

Answer 1

To calculate the heat absorbed by the silver bar, we can use the formula:

Q = m * c * deltaT

Where:

Q = heat absorbed (in Joules)

m = mass of the silver bar (in grams)

c = specific heat of silver (0.235 J/g°C)

deltaT = change in temperature (in °C)

First, we need to calculate the change in temperature:

deltaT = final temperature - initial temperature

deltaT = 55°C - 30°C

deltaT = 25°C

Now, we can plug in the values:

Q = 300g * 0.235 J/g°C * 25°C

Q = 1762.5 J

To convert Joules to kilojoules, we divide by 1000:

Q = 1762.5 J / 1000

Q = 1.7625 kJ

Therefore, the silver bar absorbs 1762.5 Joules or 1.7625 kilojoules of heat.