Answer:
We can use the formula for the test statistic for a hypothesis test of a single proportion:
z = (p-hat - p) / sqrt(pq/n)
where p-hat is the sample proportion, p is the hypothesized population proportion (0.301 according to Benford's Law), q = 1 - p, and n is the sample size.
Plugging in the values given, we get:
z = (0.2278 - 0.301) / sqrt(0.301*0.699/225) = -2.83
To find the P-value, we need to find the probability that a standard normal distribution is less than -2.83 (since this is a left-tailed test). Using a standard normal table or calculator, we find this probability to be 0.0023.
Therefore, the P-value is 0.0023.
Step-by-step explanation: