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A gas with a volume of 6.47 L at a pressure of 0.76 atm is allowed to expand until the volume raises to 62 L. What is the new pressure (in atm)?

User Aehiilrs
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We can use Boyle's Law to solve this problem, which states that the pressure of a gas is inversely proportional to its volume when the temperature and amount of gas are constant. Mathematically, we can express this as:

P1V1 = P2V2

where P1 and V1 are the initial pressure and volume, respectively, and P2 and V2 are the final pressure and volume, respectively.

Plugging in the given values, we get:

(0.76 atm)(6.47 L) = P2(62 L)

Simplifying, we get:

P2 = (0.76 atm)(6.47 L) / 62 L = 0.079 atm

Therefore, the new pressure is 0.079 atm.
User Ping
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