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A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 85 m long and 56 m

wide.
Find the area of the training field. Use the value 3.14 for x, and do not round your answer. Be sure to include the correct
unit in your answer.
3.
56 m
1
85 m
8 08
m
X

5

HD
EI

A training field is formed by joining a rectangle and two semicircles, as shown below-example-1
User Deni
by
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1 Answer

1 vote

Answer: 7221.76 m2

Explanation:

Let's first find the area of the rectangle.

The formula is lengthxwidth or LxW

Therefore the area of the rectangle is 85x56= 4760 m2

Now let's find the area of the semicircles. They are two equal semicircles, so we can put it together into one circle.

The formula for the area of a circle is πr2

They gave us the diameter not the radius, so we have to find the radius.

To find the radius, we take the diameter/2 which 56/2 = 28 m

Area= 28x28x3.14= 2461.76

The total area= 2461.76+4760= 7221.76 m2

User Max Ralph
by
7.8k points

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