Question

A 150-kg object takes 1.5 minutes to travel a 2,500-meter straight path. It begins the trip traveling 120 meters per second and decelerates to a velocity of 20 meters per second.

What was its acceleration?

Responses

(A) −1.11 m/s2


(B) −0.3 m/s2


(C) +1.11 m/s2


(D) +80 m/s2

Answer 1

Answer: So the answer is (A) -1.11 m/s^2.

Explanation: To solve this problem, we need to use the formula for average acceleration, which is given by:

a = (vf - vi) / t

Where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time.

Plugging in the values given in the problem, we get:

a = (20 m/s - 120 m/s) / (1.5 minutes * 60 seconds/minute) = -100 m/s / 90 seconds = -1.11 m/s^2

So the answer is (A) -1.11 m/s^2.