Question

159.0ml of water absorbed 7.84KJ of energy. the specific heat capacity of water is 4.184J/g.c. what is the temperature change?

Answer 1

Step-by-step explanation:

The density of water = 1 g/mL

Mass of water = 159.0 mL x 1 g/mL = 159.0 g

q = m x c x ΔT

7.84 kJ = 159.0 g x 4.184 J/g°C x ΔT

ΔT = 7.84 x 10^3 J / (159.0 g x 4.184 J/g°C)

ΔT = 11.8°C

Therefore, the temperature change is 11.9°C.