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the length of a rectangle is 4 cm less than the twice of the width. if the perimeter is 178 cm what is the width of the rectangle?​

2 Answers

5 votes

Answer:

31 cm

Explanation:

First, we choose two variables.

Let W = width.

Let L = length.

The perimeter of a rectangle is:

perimeter = 2(L + W)

Now we translate the statements of the problem into two equations.

"the perimeter is 178 cm"

2(L + W) = 178

Divide both sides by 2:

L + W = 89

"the length of a rectangle is 4 cm less than the twice of the width"

L = 2W - 4

We have a system of equations:

L + W = 89

L = 2W - 4

Rewrite the first equation:

L + W = 89

Since the second equation is already solved for L, we can easily use the substitution method.

Substitute 2W - 4 for L in the equation above.

2W - 4 + W = 89

Combine like terms on the left side.

3W - 4 = 89

Add 4 to both sides.

3W = 93

Divide both sides by 3.

W = 31

Answer: The width is 31 cm

Check:

The length is 4 cm less than twice the width. 2 × 31 cm - 4 cm = 58 cm

The length is 58 cm, and the width is 31 cm. Calculate the perimeter.

P = 2(L + W) = 2(58 cm + 31 cm) = 2(89 cm) = 178 cm

The perimeter is 178 cm as the problem states, so the answer, width = 31 cm, is correct.

User Atereshkov
by
8.8k points
5 votes

Answer: 31

Explanation:

We know that the perimeter is equal to 2W + 2L.

178 cm = 2W + 2L

We also know that the length is 4 cm less than twice the width.

L = 2W - 4

We will create a system of equations. Then we will solve with substitution.

178 cm = 2W + 2L

L = 2W - 4

178 cm = 2W + 2L

178 cm = 2W + 2(2W - 4 cm)

178 cm = 2W + 4W - 8 cm

178 cm = 6W - 8 cm

186 cm = 6W

W = 31

User Luis Vargas
by
8.9k points

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